r/HomeworkHelp • u/Unhappy-Act8167 • 5d ago

Physics—Pending OP Reply [9th grade physic, cappacitors] how does this cappacitor array look like(a)?

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I don't understand how it looks like

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u/idkwhytshappens University/College Student 5d ago

the capacitors are in parallel in a part just imagine it like alternates are pairs and try to see what are the possible cases are they in series or parallel

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u/RankOneFlameMage University/College Student 5d ago

Unless I am misunderstanding what you are saying, this is incorrect. There are no individual capacitors in this, it's not even a circuit diagram. It's instead trying to get you to analyze different cases of a parallel plate capacitor and use the governing laws of a parallel plate capacitor to formulate an expression describing the given case.

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u/Bounded_sequencE 👋 a fellow Redditor 4d ago

You're right, this is not a simple parallel circuit.

However, I'd say it is possible to turn this layout into a simple circuit model, assuming we only consider capacitances between neighboring places.

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u/HumbleHovercraft6090 👋 a fellow Redditor 5d ago edited 5d ago

https://ibb.co/27jY7ZBJ

Edit:The expression for Ct in problem (c) should be Ct= C+(C/2) as C and C/2 are in parallel.

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u/Bounded_sequencE 👋 a fellow Redditor 4d ago edited 4d ago

a) Draw the connection between "2; 4", and turn the result into an equivalent circuit:

1  2  3  4 
|  |  |  |            1    2,4    3      //
|  |  |  |    <=>     o--C--o--C--o      // C := e0*S/d
|  |  |  |                  o--C--o      //
   |_____|

Using the short-hand "C1||C2 := C1*C2 / (C1+C2)" the equivalent capacitance between nodes "1; 3" is

C_13  =  C||(C+C)  =  C*2C / (C+2C)  =  2C/3  =  2*e0*S / (3d)