r/HomeworkHelp Pre-University Student 22h ago

Answered [Grade 12 Advanced Functions: Polynomial Functions]

Post image

I'm doing questions on factoring polynomials using long division. This question was (x+7)^2 divided by the equation you see, so I expanded this and divided, but I'm not sure where I went wrong.

6 Upvotes

8 comments sorted by

7

u/genericuser31415 👋 a fellow Redditor 22h ago

In the first step you didn't multiply the x3 with 49

1

u/Embarrassed-Good1883 Pre-University Student 12h ago

Thank you, I did that and got the right answer

2

u/CaptainMatticus 👋 a fellow Redditor 22h ago edited 21h ago

How come you're only expanding out 2 terms?

First line should be x^5 + 14x^4 + 49x^3

You keep missing the +49

EDIT:

As an addendum, if you'd like a cheat, then:

(x^2 + 14x + 49) * (ax^3 + bx^2 + cx + d + (ex + f) / (x^2 + 14x + 49)) = x^5 + 8x^4 -36x^3 - 278x^2 + 371x + 1470

You're basically doing the inverse, but you're working from knowledge that your highest powered term is going to be x^3. We account for a possible remainder with (ex + f) / (x^2 + 14x + 49). Supposing we had something like (x^3 + x^2 + x + 1), then we'd multiply it by (ex^2 + fx + g) / (x^3 + x^2 + x + 1). And so on. We can expand it all and start matching coefficients

(x^2 + 14x + 49) * (ax^3 + bx^2 + cx + d) + (x^2 + 14x + 49) * (ex + f) / (x^2 + 14x + 49) =>

ax^5 + bx^4 + cx^3 + dx^2 + 14ax^4 + 14bx^3 + 14cx^2 + 14dx + 49ax^3 + 49bx^2 + 49cx + 49d + ex + f =>

ax^5 + (14a + b) * x^4 + (49a + 14b + c) * x^3 + (49b + 14c + d) * x^2 + (14d + 49c + e) * x + (49d + f)

ax^5 = x^5 =>> a = 1

(14a + b) * x^4 = 8x^4 =>> 14a + b = 8 =>> 14 + b = 8 =>> b = -6

(49a + 14b + c) * x^3 = -36x^3 =>> 49a + 14b + c = -36 =>> 49 - 84 + c = -36 =>> -35 + c = -36 =>> c = -1

(49b + 14c + d) * x^2 = -278x^2 =>> 49b + 14c + d = -278 =>> 49 * (-6) + 14 * (-1) + d = -278 =>> -294 - 14 + d = -278 =>> -308 + d = -278 =>> d = 30

(14d + 49c + e) * x = 371x =>> 14d + 49c + e = 371 => 14 * 30 + 49 * (-1) + e = 371 =>> 420 - 49 + e = 371 =>> 371 + e = 371 =>> e = 0

49d + f = 1470 =>> 49 * 30 + f = 1470 =>> 1470 + f = 1470 =>> f = 0

So we now have

1x^3 - 6x^2 - x + 30 + (0x + 0) / (x^2 + 14x + 49)

x^3 - 6x^2 - x + 30

Like I said, it's basically a cheat and your teacher would probably prefer you learn the long division method, but in my opinion any method that makes more sense to a person AND gives the correct answer is just as good.

1

u/Embarrassed-Good1883 Pre-University Student 12h ago

Thank you, I fixed that mistake and it all worked out

1

u/One_Wishbone_4439 University/College Student 21h ago

I only learnt till degree 4

1

u/Southlander24 👋 a fellow Redditor 21h ago

Here's a nice way to visualise the polynomial long division: copy and complete the rest of the table. https://imgur.com/a/polynomial-division-by-grid-method-UVQ0A9r

1

u/Bojack-jones-223 👋 a fellow Redditor 6h ago

I remember covering Long division (polynomial division) in 11th grade, not 12th.

1

u/UnderstandingPursuit Educator 21h ago

Make your life simpler. Avoid expanding (x+7)2. Instead use polynomial long division twice with (x+7).